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	<title>Comments on: How does a rock suspended in water affect the weight of the water on a scale?</title>
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	<link>http://bestwaterfilter1.com/how-does-a-rock-suspended-in-water-affect-the-weight-of-the-water-on-a-scale.htm</link>
	<description>Water Filter Systems -  House Water Filters</description>
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		<title>By: Richard W</title>
		<link>http://bestwaterfilter1.com/how-does-a-rock-suspended-in-water-affect-the-weight-of-the-water-on-a-scale.htm/comment-page-1#comment-7023</link>
		<dc:creator>Richard W</dc:creator>
		<pubDate>Mon, 08 Feb 2010 10:13:10 +0000</pubDate>
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		<description>is it 59.8 N?</description>
		<content:encoded><![CDATA[<p>is it 59.8 N?</p>
]]></content:encoded>
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	<item>
		<title>By: oldprof</title>
		<link>http://bestwaterfilter1.com/how-does-a-rock-suspended-in-water-affect-the-weight-of-the-water-on-a-scale.htm/comment-page-1#comment-7024</link>
		<dc:creator>oldprof</dc:creator>
		<pubDate>Mon, 08 Feb 2010 10:13:10 +0000</pubDate>
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		<description>The mass of water m = w/g = 9.8/9.81 ~ 1 kg.

The rock mass M = W/g = 5 kg

Total mass being weighed by the scale = 6 kg, so the weight on the scale is 58.8 N.

All that buoyancy stuff has no bearing on how much mass is sitting on the scale.</description>
		<content:encoded><![CDATA[<p>The mass of water m = w/g = 9.8/9.81 ~ 1 kg.</p>
<p>The rock mass M = W/g = 5 kg</p>
<p>Total mass being weighed by the scale = 6 kg, so the weight on the scale is 58.8 N.</p>
<p>All that buoyancy stuff has no bearing on how much mass is sitting on the scale.</p>
]]></content:encoded>
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	<item>
		<title>By: Arun</title>
		<link>http://bestwaterfilter1.com/how-does-a-rock-suspended-in-water-affect-the-weight-of-the-water-on-a-scale.htm/comment-page-1#comment-7022</link>
		<dc:creator>Arun</dc:creator>
		<pubDate>Mon, 08 Feb 2010 10:13:10 +0000</pubDate>
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		<description>scale reading=scale reading when rock is above water surface+buoyant force
=9.8+1=10.8 N ............Answer
bye ...... tkcr.............</description>
		<content:encoded><![CDATA[<p>scale reading=scale reading when rock is above water surface+buoyant force<br />
=9.8+1=10.8 N &#8230;&#8230;&#8230;&#8230;Answer<br />
bye &#8230;&#8230; tkcr&#8230;&#8230;&#8230;&#8230;.</p>
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