What is the water pressure at house a and house b in this physics problem?
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house b is 15–7.4 = 7.6 metes below the tank bottom. but we have to calculate the size of the tank to get the height of the water to the top of the tank.
density of water at 20C = 998 kg/m³
4.7e5 kg has a volume of:
4.7e5 kg / 998 kg/m³ = 471 m³
Volume of a sphere is V = ⁴/₃πr³
471 = ⁴/₃πr³
r = 4.83 meters.
d = 9.65 meters
adding that to the 7.6, we get 17.25 meters.
now to convert to pascals, which is the weight of a column of water 1 m² in area cross section.
So we have a volume of water 1 m² x 17.25 m = 17.25 m³
using the density number, that is a weight/mass of
998 kg/m³ x 17.25 m³ = 17210 kg
converting to newtons, that is 169000 newtons, which corresponds to a pressure of 169000 newtons/m² or 169000 Pascals.
That is house b. house a is unknown.
but check my arithmetic.
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